Respostas

2014-03-16T14:30:51-03:00
-3y²-6y=0
{A=-3;B-6;C=0}
Δ=-6²-4.-3.0
Δ=√36
Δ=6
-b +ou- √Δ/ 2.a
-(-6)+6/2.(-3)= 12/-6 =-2= x'
-(-6)-6/-6= 0/-6 = 0= x''