Respostas

2014-03-17T08:57:28-03:00
Q =  n.e
23,4.10^-7 = n. 1,6.10^-19

n = 23,4.10^-7
------------------------- =          resposta:  14,62. 10^12
   1,6.10^-19
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2014-03-17T10:59:25-03:00
Resposta

Q = 23,4.10⁻⁷C
e = 1,6.10⁻¹⁹

n =  \frac{Q}{e}

n =  \frac{23,4.10 ^{-7} }{1,6.10 ^{-19} }

n = 14,6.10¹²  eletrons
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