Respostas

  • Ind
  • Ambicioso
2014-03-18T19:32:55-03:00
log_{7}49 = x

 7^{x} = 49

 7^{x} =  7^{2}

x = 2 

b) log_{4}  \frac{1}{8} = x

 4^{x} =  \frac{1}{8}

  (2^{2})^{x} =  \frac{1}{ 2^{3} }

 2^{2x} =  2^{- 3}

2x = - 3 

x =  \frac{- 3}{2}

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