Respostas

2014-03-19T20:51:33-03:00
Log₂ x + log₂ (x - 2) - log₂ (x - 3) = 3

log₂ [x.(x - 2)/(x - 3)] = 3

 \frac{x.(x-2)}{(x-3)} =  2^{3} =8

x.(x-2) = 8.(x-3)

 x^{2}-2x = 8x-24

 x^{2}-10x +24=0

(x-4).(x-6)=0

x=4   ou  x=6


2014-03-19T21:22:30-03:00