Respostas

2014-03-26T00:20:06-03:00
Primeiro igualar a 0 (zero)
6x^{2}+3x+4=-8x \\ 6x^{2}+11x+4=0
3+8=11
Usar a formula de Báskhara, sendo:
a=6; b=11; c=4
D=11^{2}-4.6.4 \\ D=121-96= 25 \\ x= \frac{-11+- \sqrt{25} }{2.6}  \\ x_1= \frac{-11+5}{12}=( \frac{-6}{12}) ^{:3}= (\frac{-2}{4}) ^{:2}= \frac{-1}{2}=-0,5 \\ x_2= \frac{-11-5}{12}= (\frac{-16}{12})^{:2}=( \frac{-8}{6})^{:2}= \frac{-4}{3} = -1,333...