Respostas

2014-03-29T19:08:05-03:00
Os dados:
L1 = 45CM
L2 = ?
Ф1 = 35ºC
Ф2 = 140ºC
ΔФ = 140-35 = 105ºC
α = 5.10-6ºC-1

A conta:
ΔL = L1.α.ΔФ
ΔL = 45.5.10-6.105
ΔL = 225.10-6.105
ΔL = 23.625.10-6
ΔL = 0.023625

ACHAR O L2
ΔL = L2-L1
0.023625=L2-45
0.023625 + 45 = L2
L2 = 45.023625
1 5 1