Respostas

2013-05-26T20:32:25-03:00

y=3^x

a)y=3^2=9

b)y=3^{-1} => y=\frac{1}{3}

c)y=3^0=> 1

d)y=3^{-2}=> y=(\frac{1}{3})^2 => y=\frac{1}{9}

 

Um abraço ai.

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  • Usuário do Brainly
2013-05-27T01:43:14-03:00

a)

 

\text{y}^{\text{x}}=3^2=3\times3=9

 

b)

 

\text{y}^{\text{x}}=3^{-1}=\dfrac{1}{3^1}=\dfrac{1}{3}

 

c)

 

\text{y}^{\text{x}}=3^{0}=1

 

d)

 

\text{y}^{\text{x}}=3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}