Respostas

2013-05-28T20:47:20-03:00

Acho que é assim:

(2x-1).(2x-1)=-8(2x+1)
4x²-2x-2x+1=-16x-8
4x²-4x+1+16x+8=0
4x²+12x+9=0

Δ=b²-4ac
Δ=12²-4.4.9
Δ=144-144
Δ=0

X= -b±√Δ/ 2a

X=-12±√0 / 2.4

X=-12±0 / 8


X' e X" = -12/8 = -3/2