Respostas

2014-04-06T00:58:54-03:00
Boa noite Oseias!
Vamos começar a simplificar,

\frac{(2^{-2}+ 4^{-3})}{ (4^{-2}+ 8^{-2})} =    \frac{ ( \frac{1}{2})^{2}+(\frac{1}{4})^{3}}{  (\frac{1}{4})^{2} +   (\frac{1}{8})^{2}   } =   \frac{\frac{1}{4}+ \frac{1}{64}  }{ \frac{1}{16}+ \frac{1}{64}  } =  \frac{ \frac{17}{64}}{ \frac{5}{64} }  =   \frac{17}{64}. \frac{64}{5}  =  \frac{1088}{320} = 3,4

Abraço!


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