Respostas

2014-04-10T16:34:41-03:00
 \sqrt{(3+3)^2+(y-6)^2} =10
6² +(y - 6)² = 100
(y - 6)² = 64
y - 6 = +,-√64

se y - 6 = +8 ==> y = 14
Se y - 6 = -8 ==>  y = -2

Logo y = 14  ou  y = -2
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