Respostas

  • Usuário do Brainly
2013-02-19T00:15:58-03:00

Seja \text{P}=\dfrac{\sqrt{3}+1}{\sqrt{3}-1}+\dfrac{\sqrt{3}-1}{\sqrt{3}+1}

 

Desta maneira, temos que:

 

\text{P}=\dfrac{(\sqrt{3}+1)^2+(\sqrt{3}-1)^2}{(\sqrt{3}-1)\cdot(\sqrt{3}+1)}

 

Donde, obtemos:

 

\text{P}=\dfrac{3+2\sqrt{3}+1+3-2\sqrt{3}+1}{3-1}

 

\text{P}=\dfrac{8}{2}=4

1 5 1