Respostas

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2014-04-11T00:15:38-03:00

Lo = 5
α = 2×10⁻⁶
ΔO = 50

ΔL = 5 × 2 × 10⁻⁶ × 50

ΔL = 5 × 10⁻⁴


L final = 5 + 0,0005 = 5,0005m

2 5 2
2014-04-11T00:33:19-03:00
Delta L= 2x10-6 . 5. 50=
delta L=2x10-6 .250= 250x2 e conserva o 10-6
delta L=500x10-6= 5x10-4 ou 
delta L= 0,0005
comprimento final= 5+0,0005=5,0005m