Respostas

A melhor resposta!
2014-04-13T12:44:19-03:00
Usando as propriedades de logaritmos:
LOG( X . Y ) = LOGX + LOGY e LOG ( X / Y ) = LOGX - LOGY 

 TEMOS: log2 = a e log3 = b

log6 = log2 + log3 = a + b
log12 = log2 + log2 + log3 = 2a + b
log1,5 = log3/2 = log3 - log2 = b - a
log0,25 = log1/4 = log1 - ( log2 + log2 ) = 0 - 2a = - 2a
log5 = log10/2 = log10 - log2 = 1 - a
log180 = log2 + log2 + log3 + log3 + log5 = 2a + 2b + 1 - a = a + 2b + 1
log500 = log2 + log2 + log5 + log5 + log5 = 2a + 3 . ( 1 - a ) = 2a + 3 - 3a = 3 - a

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