Respostas

2014-04-15T10:11:37-03:00
3x ao quadrado -4x-2=-3

3x² - 4x - 2 = - 3
3x² - 4x -2 + 3 = 0

3x² - 4x  +1 = 0                 a = 3             b = -4             c = 1
Δ= b² - 4ac
Δ= (-4)² - 4(3)(1)
Δ= 16 - 12
Δ= 4        se   Δ>0    então     x= -b +- √Δ/2a

x' = -(-4) - √4/2(3)
x' = 4 - 2/6
x' = 2/6_____________x' = 1/3

x" = -(-4) + 2/6
x" = 4 + 2/6
x" = 6/6_____________x" = 1