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2014-04-20T18:09:54-03:00
Componente vertical :

Seno 60^0 =  \frac{Vy}{20}

 \frac{  \sqrt{3} }{2}  =  \frac{Vy}{20}

Vy = 10 \sqrt{3} m/s

componente horizontal :

cos 60^0 =  \frac{Vx}{20}

 \frac{1}{2}  =  \frac{Vx}{20}

Vx = 10 m/s
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