Respostas

2014-04-23T16:28:02-03:00
(x² + 3x) ≥ (x - 1) => x² + 3x - x + 1 ≥ 0 => x² + 2x + 1 ≥ 0 => (x+1)² ≥ 0 => x+1≥√0 =>  => x+1 ≥ 0 => x ≥ 1.
S = { x∈ IR / x ≥ 1}
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