Respostas

2013-06-16T15:42:08-03:00

sen² + cos² = 1

 

\frac{3^2}{5^2} + cos² = 1

 

cos² = 1 - \frac{9}{25}

 

cos² = \frac{16}{25}

 

cos = \frac{4}{5}

 

tg = \frac{sen}{cos}

 

tg = \frac{\frac{3}{5}}{\frac{4}{5}}

 

tg = \frac{3}{5} \cdot \frac{5}{4} = \frac{15}{20} = \frac{3}{4}

1 3 1