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2014-05-19T21:23:09-03:00
Primeiro calculamos 2A

2.  \left[\begin{array}{ccc}6&3&-2\\-5&2&8\\\end{array}\right] =   \left[\begin{array}{ccc}12&6&-4\\-10&4&16\\\end{array}\right]

agora calculamos 3A

3.  \left[\begin{array}{ccc}6&3&-2\\-5&2&8\\\end{array}\right] =   \left[\begin{array}{ccc}18&9&-6\\-15&6&24\\\end{array}\right]

por fim , é só somar as matrizes obtidas acima

  \left[\begin{array}{ccc}12&6&-4\\-10&4&16\\\end{array}\right] +   \left[\begin{array}{ccc}18&9&-6\\-15&6&24\\\end{array}\right] =  \boxed{ \left[\begin{array}{ccc}30&15&-10\\-25&10&40\\\end{array}\right] }
3 5 3