Respostas

2014-05-25T14:57:57-03:00
X² - 3x -6 + 8 = 0
x² - 3x +2 = 0

x= (-b +- √b² - 4ac) / 2a

x= +3 +- √ (-3)² - 4 (1)(2) ] 2

x = (3 +-1)2

x1=1
x2=2

1 5 1
2014-05-25T15:02:06-03:00
 x² + 3x - 6 = -8
x² + 3x - 6 + 8 = 0
x² + 3x + 2 = 0
a = 1
b = 3
c = 2
Δ = b² - 4ac
Δ= (3)² - 4(1)(2)
Δ = 9 - 8
Δ= 1
se
Δ > 0
então
x= - b -+
√Δ/2a

x' = -3 -√1/2(1)
x' = - 3 - 1/2
x' = - 4/2
x' = - 2

x" = -3 + √1/2(1)
x" = -2/2
x" = -1

as suas raizes são V = {-2, -1}