Respostas

2014-05-25T18:49:09-03:00
A= 1
B = 8 
C= 12
Delta = b² - 4ac
Delta = 16
x= -b +- raiz de delta / 2a
x = -2
x¹ = -6
2014-05-25T19:02:15-03:00
na equação
 x²+8x+12=0                                                                                                                 
temos a=1 b=8 c=12                                                                                                            para calcular faremos a equação de Báskara logo                                                             Δ=b²-4ac
Δ=8²-4.1.12
Δ=64-48
Δ=16                                                                                                                                
sendo assim faremos
(b+ou-√Δ)/2a                                                                                                                
assim ficará                                                                                                   (8+ou-√16)/2                                                                                                                dando(8+4)/2=6           e          (8-4)/2=2
os números da segunda equação são negativos.
dando -6 e -2
que esqueci de colocar
obrigado por esclarecer minhas duvidas.
Disponha.