Respostas

2014-05-27T16:00:00-03:00
F(x)= (m + 3) x² +8x - 1
f '(x)= 2(m + 3) x+8
2(m + 3) x+8=0
2(m + 3) x=-8
(m + 3) x=-4
x=-4/(m+3)

f(-4/(m+3))= (m + 3) (-4/(m+3))² +8(-4/(m+3)) - 1=3
16/(m+3)-32/(m+3)=3+1
-16/(m+3)=4
-16=4(m+3)
(m+3)=-4
m=-4-3
m=-7