Respostas

2013-07-01T12:54:32-03:00

Q1+Q2=0

 

Q=m*c*/\t

 

1000 * 1 * (tf-70) + 2000*1* (tf-10) = 0

 

1000tf - 70.000 + 2000tf - 20.000 = 0

 

3000tf - 90.000 = 0

 

3000tf = 90.000

 

tf= 90.000/3000

 

tf=30°C

 

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A temperatura final dos 3kg de água é 30°C

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