Respostas

2013-07-03T19:55:36-03:00

32-40i-8i+10i²=0
10i²-48i+32=0 (simplifica por 2)
5i²-24i+16=0

 

a=5
b= -24
c= 16

 

Delta= b²- 4*a*c
Delta= (-24)²-4*5*16
Delta= 576- 320
Delta= 256

 

x¹= -b+VDelta/2*a
x¹= - (-24) + V256/2*5
x¹= 24+16/10
x¹= 40/10
x¹=4

 

x²= -b-VDelta/2*a
x²= - (-24) - V256/ 2*5
x²= 24 - 16 /10
x²= 8 /10 (simplifica por 2)
x²= 4/5