Respostas

  • Usuário do Brainly
2014-06-03T19:49:58-03:00
O volume desse tronco limitado pelos planos será igual ao volume da pirâmide original menos o volume da pirâmidezinha, menos o volume do tronco menos.

V(o)-->Volume original
V(c)-->Volume da pirâmidezinha
V(t)-->Volume tronco menor
V(l)-->Volume limitado
V(m)-->Volume piramide média

~~V(o)=b.h/3

b/b(o) = (h/h/3)²
b(o)=b/9

V(c)=b(o).h/3.1/3
V(c)=b/9.h/3.1/3

~~V(c)=b.h/81

V(t)=V(o)-V(m)

b/b(m)=(h/2h/3)²
b/b(m)=9/4
b(m)=4b/9

h(m)=2h/3

V(m)=2h/3.4b/9.1/3
V(m)=8.b.h/81

V(t)=(1/3 - 8/81)b.h
V(t)=19.b.h/81

V(l)=V(o)-V(c)-V(t)
V(l)=bh/3-bh/81-19bh/81
V(l)=(1/3-1/81-19/81)bh
V(l)=7.b.h/81