Respostas

2014-06-14T13:41:59-03:00
92g/ml----------------100%
X --------------------------30,43%N(nitrogenio)
X~= 28g
92g/ml--------------------100%
X-------------------------------69,57%O(oxigenio)
X=64g
N2O4
(N2= 14*2= 28)
(O4=16*4=64)
2014-06-15T00:00:01-03:00
Se for 92 g/mol basta utilizar regra de três;

30,43%/100% * 92 / 14u N = ~ 2
69,57%/100% * 92 / 16u O = ~4

N₂O₄