Respostas

2013-07-17T20:03:23-03:00
Q=m*c*/\t
QS_Gelo=50*0,5*(0-(-20)
Q=25 * 20
Q= 500 calorias

QF_Gelo=m*L
Q=50*80
Q=4000 calorias

QS_agua = 50*1*(40-0)
Q=50*40
Q=2000 Calorias

Quantidade de Calor QC = 500 + 4000 + 2000 = 6500cal

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Q= 6500cal = 6,5kCal.
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