Respostas

  • Usuário do Brainly
2014-06-24T15:00:01-03:00
F(x)= x² -6x +m
f(1)=2

1² -6(1) +m=2
1-6 +m=2
m=2 +6 -1
m=7

f(x)= x²-6x +7

x² -6x +7=0
Δ=36-28=8
√Δ=2√2

x=  \frac{6 +2 \sqrt{2} }{2} =  \frac{2(3 + \sqrt{2)} }{2}  = 3+ \sqrt{2}

x'=3 +√2

x"= 3 -√2

S={3+√2, 3- √2 }

valor numérico
f(2 +√3)

x² -6x +7=0

(2 +√3)² -6( 2 +√3) +7=0
4 +2√3 +3 -12 -6√3 +7=0

2 -4√3