Respostas

  • Usuário do Brainly
2014-06-24T23:56:47-03:00
F(x)=x²-5x -6
x² -5x -6=0
Δ=25+24=49
√Δ=7

x'= \frac{5+7}{2} = \frac{12}{2} =6

x" \frac{5-7}{2} = \frac{-2}{2} =-1

S={-1,6}

xv= \frac{-b}{2a} = \frac{5}{2}

yv=-Δ/4a= \frac{-49}{4}

v( \frac{5}{2} , \frac{-49}{4} )


f(x)=-x²+2x+2
-x²+2x +2=0  (:por -1)
x²-2x-2=0
Δ=4-8=-4
√-4 não existe

s={  }

xv= \frac{-b}{2a} = \frac{2}{2} =1

yv=-Δ/4a= \frac{4}{4} =1

V(1,1)