Respostas

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2014-06-25T20:51:54-03:00
CB=B-C OU SEJA(1-3,2-2,-1-1)=(-2,0,-2)
2CA=2(A-C)=(-1,-3,1) =(-2,-6,2)
BC=C-B=(2,0,2)
LOGO CB*(BC-2AC)=(-2,0,-2)*(4,6,0)=(-8,0,0)
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