Respostas

2014-06-26T22:35:56-03:00
Se for a quantidade de mol:
0,17mol-----1000ml
x---------100ml
x=0,017
2 5 2
2014-06-27T11:53:45-03:00
CH3COOH--- ácido etanóico ( peso molar= 60,05)
1 mol__________60,05g
0,1700mol_______X
0,1700*60,05/1
= 10,20 g

1000ml_______10,20g
100ml________X
100*10,20/1000
= 1,02 g de CH3OOH
1 5 1