Respostas

  • Usuário do Brainly
2014-06-27T16:49:27-03:00
Cos²x + sen²x=1

( \frac{7}{25}) ^{2}  +sen ^{2}x =1

 \frac{49}{625} +sen ^{2} x=1

sen²x=1+  \frac{49}{625}

sen²x= \frac{576}{625}

senx=   \sqrt{ \frac{576}{625} } =

senx=+ ou - \frac{24}{25}
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