Respostas

2014-06-29T12:52:06-03:00
 \frac{3 x^{2} }{8}- \frac{9}{8} = \frac{2x-1}{4}   \\  \frac{3 x^{2} -9}{8} = \frac{2x-1}{4} \\  \frac{3 x^{2} -9 = 2(2x-1)}{8}  \\ 3 x^{2} -9 =4x-2 \\ 3 x^{2} -4x-9+2=0 \\ 3 x^{2} -4x-7=0

Δ = b² - 4.a.c 
Δ = -4² - 4 . 3 . -7 
Δ = 16 - 4. 3 . -7 
Δ = 100

x = (-b +- √Δ)/2a
x' = (--4 + √100)/2.3           x'' = (--4 - √100)/2.3
x' = 14 / 6                           x'' = -6 / 6
x' =  7/3                              x'' = -1