Respostas

2014-06-29T12:38:56-03:00
)  2x (4x-2) - 4 = 0

 8 x² -4x-4=0 

Δ=4²-4.8.(-4)

Δ=16+128

Δ=144

x'= \frac{ -(-4)+ \sqrt{144} }{2.8} = \frac{4+12}{16} = \frac{16}{16} = 1

x''= \frac{4-12}{16}=  \frac{-8}{16} =  \frac{-1}{2}

S={ \frac{-1}{2} , 1}