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2014-06-29T23:23:10-03:00
Relembrando a regra de L'Hospital
 \lim_{x \to a}  \frac{f(x)}{g(x)} =  \lim_{x \to a}  \frac{f'(x)}{g'(x)}



 \lim_{x \to +\infty}  \frac{ln x}{ \sqrt{x} }  =>   \lim_{x \to +\infty}  \frac{ \frac{1}{x} }{  \frac{1}{2 \sqrt{x} }  }

 \lim_{x \to +\infty}  \frac{2}{ \sqrt{x} } => 2 \lim_{x \to +\infty}  \frac{1}{ \sqrt{x} } => 2 * 0 = > 0

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