Respostas

2014-07-01T12:31:50-03:00
8^{2x+1}= \sqrt[3]{4^{x-1} }\\
(2^3)^{2x+1}= \sqrt[3]{(2^{2})^{x-1}  }\\
2^{6x+3}= \sqrt[3]{2^{2x-2} }\\\\
2^{6x+3}=2^{ \tfrac{2x-2}{3} }\\\\
\not2^{6x+3}=\not2^{ \tfrac{2x-2}{3} }\\\\
6x+3= \dfrac{2x-2}{3}\\\\
3(6x+3)=2x-2\\
18x+9=2x-2\\
18x-2x=-2-9\\
16x=-11\\\\
x=- \dfrac{11}{16}\\\\
S=\left\{- \dfrac{11}{16}\right\}

Espero ter ajudado e tenha ótimos estudos =))
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