Respostas

2014-07-07T06:34:16-03:00
A) 405
sen =   \frac{\sqrt{2} }{2}
cos =  \frac{\sqrt{2} }{2}
tg = 1

B) 840
sen =   \frac{\sqrt{3} }{2}
cos =  \frac{-1}{2}
tg = - \sqrt{3}

C) 1290
sen =  \frac{-1}{2}
cos = -  \frac{ \sqrt{3} }{2}
tg =  \frac{ \sqrt{3} }{3}

D) 1740
sen = -  \frac{ \sqrt{3} }{2}
cos =  \frac{1}{2}
tg = -  \sqrt{3}

E) 120
sen =  \frac{ \sqrt{3} }{2}
cos = -  \frac{1}{2}
tg = -  \sqrt{3}

F) 240
sen = -  \frac{ \sqrt{3} }{2}
cos = -  \frac{1}{2}
tg =  \sqrt{3}

G) 315
sen = -  \frac{ \sqrt{2} }{2}
cos =  \frac{ \sqrt{2} }{2}
tg = -1

H) 1230
sen =  \frac{1}{2}
cos = -  \frac{ \sqrt{3} }{2}
tg = -  \frac{ \sqrt{3} }{3}
4 3 4