Respostas

2014-07-09T00:16:05-03:00
 \frac{ x^{2} }{3}-2x+3 =0  \\  \\  \frac{ x^{2} -6x+9=0}{3}  \\  \\  x^{2} -6x+9 =0

Δ = b² - 4.a.c 
Δ = (-6)² - 4 . 1 . 9 
Δ = 36 - 4. 1 . 9 
Δ = 0

x = (-b +- √Δ)/2a
x' = (-(-6) + √0)/2.1        x'' = (-(-6) - √0)/2.1
x' = 6 / 2                      x'' = 6 / 2
x' = 3                            x'' = 3
1 5 1