Respostas

2014-07-10T10:27:31-03:00
(-2x+1)(3x-6) > 0 (multiplica cada termo do primeiro por cada termo do segundo)
-6x²+12x+3x-6 > 0
-6x²+15x-6 > 0 (÷3)
-2x²+5x-2 > 0
-2x²+5x-2 = 0
Bhaskara: Δ = b²-4.a.c = 5² - 4.(-2).(-2) = 25 -16 = 9
x' =  \frac{-5+ \sqrt{9} }{2.(-2)} =  \frac{-5+3}{-4}  \frac{-2}{-4}  =  \frac{1}{2}  
x" =  \frac{-5- \sqrt{9} }{2.(-2)}  \frac{-5-3}{-4}  \frac{-8}{-4}  = 2
x>  \frac{1}{2}  
x>2
S= {x∈R | x> \frac{1}{2}  ou x>2} 

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