Respostas

2014-07-11T21:25:55-03:00
F(2) = 2^2 + 2b +c

-3 = 0^2 + 0 + c -> c = -3

-1 = 1^2 +b -3
b = -1 -1 +3 -> b = 1

f(2) = 2^2 + 2*1 -3 <=> f(2) = 4+2-3 = 3
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2014-07-11T22:05:33-03:00
F(x) = x² + bx + c
f(0) = -3 => -3 = (0)² + b.0 + c => c = -3 
f(1) = -1 => -1 = 1 + b + c => b + c = -2 => b - 3 = -2 => b = -2 + 3 => b = 1
..........
f(x) = x² + x - 3
f(2) = (2)² + (2) - 3 => f(2) = 4 + 2 - 3 => f(2) = 3
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