Respostas

2014-07-12T12:30:00-03:00
x-8= \frac{5x-8}{x-3}  \\ (x-8).(x-3)=5x-8 \\  x^{2} -3x-8x+24=5x-8 \\  x^{2} -11x+24=5x-8 \\ x^{2} -11x+24-5x+8=0 \\ x^{2} -16x+32=0
basta agora você resolver baskara