Respostas

2014-07-16T14:47:28-03:00
\setlength{\unitlength}{0,8cm}
\begin{picture}(6,5)
\put(1,1){\line(0,1){3}}\put(1,1){\line(1,0){4}}
\put(1,4){\line(4,-3){4}}
\put(0.6,0.8){\textit{A}}\put(5.05,0.8){\textit{B}}\put(0.6,4.05){\textit{C}}\put(3,2.55){\textit{20}}\put(0.4,2.5){\textit{16}}\put(2.95,0.6){\textit{12}}\put(1,1.2){\line(1,0){0.2}}\put(1.2,1){\line(0,1){0.2}}\end{picture} \\ \\ \angle ABC = x \\  \\ \angle BCA = y \\  \\a) sen \ x =16/20 = 0,8 \\  \\ b) cos \ x = 12/20 = 0,6 \\  \\ c) tg \ x = 16/12=1,333 \\  \\

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d)sen \ y= 12/20 = 0,6 \\ \\ e) cos \ y = 16/20=0,8 \\ \\ f) tg \ y=12/16=0,75

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Utilizei:

tg α = cat. oposto/ cat. adjacente

cos α = cat adjacente/hipotenusa

sen α = cat. oposto/hipotenusa

obs: Não consegui colocar o ângulo dentro do triângulo
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