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  • Usuário do Brainly
2014-07-20T19:48:16-03:00
 \frac{AB}{BC} = \frac{DE}{EF}

 \frac{1}{1,5} = \frac{2}{x}

x=2.1,5=3

med(EF)=3cm


 \frac{SB}{BT} = \frac{AB}{BC}

 \frac{3}{4} = \frac{2}{y}

y= \frac{2.4}{3} = \frac{8}{3}
AC=2+ \frac{8}{3}= \frac{14}{3} cm


 \frac{PR}{QR} = \frac{ST}{BT}

 \frac{3,5}{x} = \frac{7}{4}

x= \frac{3,5.4}{7} = \frac{14}{7} =2

PQ=PR-QR
PQ=3,5-2
PQ=1,5cm



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