Respostas

2013-07-31T22:39:12-03:00
Calculando o perímetro, temos:

2p_{ret\hat{a}ngulo}=2(\sqrt{5}+1)+2(\sqrt{5}-1)\\\\
2p_{ret\hat{a}ngulo}=2\sqrt{5}+2+2\sqrt{5}-2\\\\
2p_{ret\hat{a}ngulo}=4\sqrt{5}

Calculando a área, temos:

A_{ret\hat{a}ngulo}=(\sqrt{5}+1)\times(\sqrt{5}-1)\\\\A_{ret\hat{a}ngulo}=5-1\\\\A_{ret\hat{a}ngulo}=4