Respostas

2014-07-21T22:13:13-03:00
A-)

n =  \frac{Q}{e} = \frac{1,6.10^{-19} }{3,2} = 0,5.10^{-19}

n=  5.10^{-20} elétrons

b-)

Q = n.e

Q = 1,6.10^{-19} .  5.10^{20}

 Q = 8.10^{1}

Q= 80 C