Respostas

2014-07-22T16:45:58-03:00
T = 27ºC + 273 = 300 k                  v= 6 L
t'= 327ºC + 273 = 600 k                v'=?

 \frac{v}{t}=  \frac{v'}{t'} 



v' = \frac{v.t'}{t}

v' = \frac{6.600}{300}

v' = 12 L