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2014-07-22T17:33:25-03:00
4-) F= k. \frac{Q_{1}.Q_{2}}{d^{2} }

d = 70 cm = 0,7 m
k= 9.10^9

F= 9.10^{9} . \frac{10^{-6} .6.10^{-6}}{0,7 ^{2} } =  \frac{54.10^{9}. 10^{-12}  }{0,49}

F = \frac{54.10^{-3} }{0,49 } 


F = 0,1102 N

5-) F= k. \frac{Q}{d^{2} }

F= k. \frac{Q}{d^{2} } > F. d^{2} = k.Q

Q =  \frac{F.d^{2} }{k} =  \frac{3,6.1^{2} }{9.10^{9} } = 0,4.10^{-9}

Q = 4.10^{-8} C
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