Respostas

2013-08-01T19:40:30-03:00
Desenvolvendo o cálculo, temos:

(\dfrac{2pq^{2}}{u^{2}v})^{2}\cdot(\dfrac{4p^{2}q}{uv^{2}})^{-2}=(\dfrac{2pq^{2}}{u^{2}v})^{2}\cdot(\dfrac{uv^{2}}{4p^{2}q})^{2}=\dfrac{4p^{2}q^{4}}{u^{4}v^{2}}\cdot\dfrac{u^{2}v^{4}}{16p^{4}q^{2}}=\dfrac{q^{2}v^{2}}{4u^{2}p^{2}}\\\\
\Longrightarrow(\dfrac{2pq^{2}}{u^{2}v})^{2}\cdot(\dfrac{4p^{2}q}{uv^{2}})^{-2}=\dfrac{q^{2}v^{2}}{4u^{2}p^{2}}