Respostas

2014-07-23T18:38:15-03:00
 9x4-13x²+4=0
9(x²)²- 13x²+ 4 = 0

y = x²

9y² - 13y+ 4= 0

Δ = b² - 4ac
Δ= 13² - 4.9.4
Δ = 169 - 144= 25

y=  \frac{-b + \sqrt{delta} }{2a} =  \frac{13+ \sqrt{25} }{2.9} =  \frac{13+5}{18} =   1

y'=  \frac{- (-13) - \sqrt{25} }{2.9} =  \frac{13 - 5}{18} =   \frac{4}{9}

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