Respostas

2014-07-27T16:36:20-03:00
Do enunciado :

2x^2=7x-3\\2x^2-7x+3=0\\
\\\Delta=(7)^2-4*2*3\\\Delta=25\\
\\x= \frac{-b\pm \sqrt{\Delta} }{2a} \\
\\x= \frac{7\pm5}{4} \\
\\x'=3\\
\\x''= \frac{1}{2}

No caso os números são 3 e 1/2