Respostas

2014-07-30T10:20:37-03:00
Equação biquadrada.

x^4+x^2-2=0

x^4→ y^2
x^2→ y

y^2+y-2=0\\
\\y= \frac{-1\pm3}{2} \\
\\y'=1\\y''=-2

x= \sqrt{y'} \\x= \sqrt{y''} \\
\\x=\pm1\\
\\x=\pm~i \sqrt{2}

\boxed{S=\{1,-1, -i \sqrt{2},i \sqrt{2}  \}}